Find the average velocity for an object between t = -1 sec and t = -0.9 sec if f(t) = 5sin(t) + 5 represents its position in feet. (Round to the nearest thousandth.)
A) 2.702
B) 3.108
C) 2.907
D) -2.907

Question

Quizplus · Accepted Answer

The velocity can be found by taking the derivative of the position function:

f'(t) = 5cos(t)

The average velocity between t = -1 sec and t = -0.9 sec can be found by taking the average of the velocities at those two times:

f'(-1) = 5cos(-1) = 2.077 
f'(-0.9) = 5cos(-0.9) = 3.736

Average velocity = (f'(-1) + f'(-0.9))/2 = (2.077 + 3.736)/2 = 2.907

Therefore, the best choice is C) 2.907.

Find the Average Velocity for an Object Between T =