When a spring is stretched and then released, it oscillates according to two laws of physics: Hooke's Law and Netwon's Second Law. These two laws combine to form the following differential equation in the case of free, undamped oscillation: where m is the mass of an object attached to the spring, x is the distance the spring is stretched beyond its standard length with the object attached (its equilibrium point) , t is time, and k is a constant associated with the strength of the spring. Consider a spring with
from which is hung a 40-pound weight. The spring with the weight attached stretches to its equilibrium point. The spring is then pulled 7 feet farther than its equilibrium and released. Find a particular solution for the position of the spring after time t. Use the fact that
, where g is the gravitational constant 32 feet per second per second, and that when the spring is first released, its velocity is zero. Round the coefficients to three decimal places.
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Correct Answer:
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