To show that is not the limit of
as
we should show that:
A) For any , there exists
such that if
then
.
B) For any , there exists
such that if
then
.
C) There exists , such that for any
the inequalities
and
have a solution
.
D) There exist and
such that if
then
.
E) A and C are correct.
Correct Answer:
Verified
Q87: Suppose there exists Q88: Which of the following functions has a Q89: Which of the following properties can be Q90: To show that Q91: Compute the following limits: Q92: The Intermediate Value Theorem guarantees that the Q93: The polynomial Q94: The following function is a counterexample for Q96: The following function is a counterexample for Q97: Find Unlock this Answer For Free Now! View this answer and more for free by performing one of the following actions Scan the QR code to install the App and get 2 free unlocks Unlock quizzes for free by uploading documents
A)