A mass of 0.40 kg,hanging from a spring with a spring constant of 80 N/m,is set into an up-and-down simple harmonic motion.What is the speed of the mass when moving through the equilibrium point? The starting displacement from equilibrium is 0.10 m.
A)zero
B)1.4 m/s
C)2.0 m/s
D)3.4 m/s

Question

Quizplus · Accepted Answer

The maximum speed in simple harmonic motion occurs at the equilibrium point and is given by v_max = ωA, where ω = sqrt(k/m) and A is the amplitude. Here, ω = sqrt(80/0.40) = 14.14 rad/s and A = 0.10 m, so v_max = 14.14 * 0.10 = 1.414 m/s.

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