A 12-V battery is connected in series with a switch,6.0-W resistor and coil.What energy is stored in the coil when the current is 2.0 A? The time constant is 4.0 x 10^-4 s. A)4.8 x 10^-3 J B)9.6 x 10^-3 J C)14 x 10^-3 J D)29 x 10^-3 J

Question

Quizplus · Accepted Answer

The energy stored in an inductor is given by the equation E = 1/2 * L * I^2, where L is the inductance of the coil and I is the current flowing through it. In this case, the current is 2.0 A and the inductance is given by the time constant, which is 4.0 x 10^-4 s. Therefore, the energy stored in the coil is E = 1/2 * 4.0 x 10^-4 s * (2.0 A)^2 = 4.8 x 10^-3 J.

A 12-V Battery Is Connected in Series with a Switch,6