A large jetliner with a wingspan of 40 m flies horizontally and due north at a speed of 300 m/s in a region where the magnetic field of the earth is 60 µT directed 50 $\degree$ below the horizontal.What is the magnitude of the induced emf between the ends of the wing?
A)250 mV
B)350 mV
C)550 mV
D)750 mV

Question

Quizplus · Accepted Answer

The induced emf between the ends of the wing can be calculated using the formula: 
emf = (B x L x v x sinθ) 
where B is the magnetic field strength, L is the length of the wing (which we can assume to be equal to its wingspan), v is the velocity of the plane, and θ is the angle between the magnetic field and the plane's velocity vector. 
Substituting the given values, we get: 
emf = (60 x 10^-6 T) x (40 m) x (300 m/s) x sin(50°) 
emf = 0.55 V or 550 mV (rounded to 3 significant figures) 
Therefore, the correct choice is (C).

A Large Jetliner with a Wingspan of 40 M Flies °\degree°

A Large Jetliner with a Wingspan of 40 M Flies $\degree$