What is the average power dissipation in an RLC series circuit in which R = 100 W,L = 0.1 H,and C = 10 µF driven at resonance by a 100-V (rms)source?
A)100 W
B)500 W
C)1 000 W
D)2 W

Question

Quizplus · Accepted Answer

At resonance, the impedance of the circuit is purely resistive and equals the resistance R. The average power dissipation is given by P = V^2/R, where V is the rms voltage. Thus, P = (100^2)/100 = 100 W.

What Is the Average Power Dissipation in an RLC Series