A proton with mass 1.67 x 10^-27kg moves with a speed of 0.600 c in an accelerator.What is its relativistic momentum? (c = 3.00 x 10⁸ m/s) A)0.530 x 10^-19 kg*m/s B)2.40 x 10^-19 kg*m/s C)3.76 x 10^-19 kg*m/s D)6.67 x 10^-19 kg*m/s

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Quizplus · Accepted Answer

The relativistic momentum is given by p = γmv, where γ = 1/√(1-v²/c²). For v = 0.600c, γ ≈ 1.25. Thus, p = 1.25 * 1.67 x 10⁻²⁷ kg * 0.600 * 3.00 x 10⁸ m/s ≈ 3.76 x 10⁻¹⁹ kg·m/s.

A Proton with Mass 1