The S⁺,S⁰,and S^- all have strangeness of (-1).The collision of a proton and a neutron to produce a S⁰ and an anti-S^- cannot occur because it does not conserve: A)strangeness. B)charge. C)baryon number. D)All of the above.

Question

Quizplus · Accepted Answer

The conservation of baryon number is violated in this case. The initial particles, a proton and neutron, have a total baryon number of 2. The final particles, S⁰ and anti-S^-, have a total baryon number of 1 + (-1) = 0. Therefore, baryon number is not conserved in this process. Strangeness and charge are conserved, as all the particles involved have a net strangeness and charge of zero.

The S+,S0,and S- All Have Strangeness of (-1)

The S⁺,S⁰,and S^- All Have Strangeness of (-1)