A 10.0-kg mass is placed on a 25.0 $\degree$ incline and friction keeps it from sliding.The coefficient of static friction in this case is 0.580,and the coefficient of sliding friction is 0.520.The mass is given a shove causing it to slide down the incline.What is the frictional force while the mass is sliding?
A)41.4 N
B)88.8 N
C)46.2 N
D)51.5 N

Question

Quizplus · Accepted Answer

To find the frictional force while the mass is sliding, we need to use the coefficient of sliding friction since it is in motion. The force of friction, Ff, can be calculated using the formula:

Ff = μkN

where μk is the coefficient of sliding friction and N is the normal force.

The normal force, N, can be found by resolving the weight of the mass into components parallel and perpendicular to the incline. The perpendicular component is balanced by the normal force, while the parallel component is responsible for the force of friction.

The weight of the mass is:

mg = 10.0 kg x 9.81 m/s² = 98.1 N

The perpendicular component is:

N = mg cos θ = 98.1 N x cos 25° = 89.2 N

The force of friction is:

Ff = μkN = 0.520 x 89.2 N = 46.2 N

Therefore, the answer is C) 46.2 N.

A 100-Kg Mass Is Placed on a 25 °\degree° Incline and Friction Keeps It from Sliding

A 100-Kg Mass Is Placed on a 25 $\degree$ Incline and Friction Keeps It from Sliding