A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate.What is the acceleration of the crate if the 750-N force is maintained after the crate begins to move and the coefficient of kinetic friction is 0.12? A)1.8 m/s² B)2.5 m/s² C)3.0 m/s² D)3.8 m/s²

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Quizplus · Accepted Answer

The net force is the applied force minus the force of kinetic friction. The force of kinetic friction is 0.12 times the normal force (which is the weight of the crate, 250 kg * 9.8 m/s²). The net force is then divided by the mass to find acceleration: (750 N - (0.12 * 250 kg * 9.8 m/s²)) / 250 kg = 1.8 m/s².

A Horizontal Force of 750 N Is Needed to Overcome