A simple pendulum,2.0 m in length,is released with a push when the support string is at an angle of 25 $\degree$ from the vertical.If the initial speed of the suspended mass is 1.2 m/s when at the release point,what is its speed at the bottom of the swing? (g = 9.8 m/s²) A)2.3 m/s B)2.6 m/s C)2.0 m/s D)0.5 m/s

Question

Quizplus · Accepted Answer

Using conservation of energy, the initial potential energy and kinetic energy are converted into kinetic energy at the bottom. The initial potential energy is mgh, where h = 2 - 2cos(25°). The initial kinetic energy is 0.5 * m * (1.2)^2. At the bottom, all energy is kinetic: 0.5 * m * v^2. Solving for v gives approximately 2.3 m/s.

A Simple Pendulum,2 °\degree° From the Vertical

A Simple Pendulum,2 $\degree$ From the Vertical