It is impossible to get short-circuit behavior for overloaded operator && or operator ||

Question

Quizplus · Accepted Answer

Overloaded operator && and operator || do not preserve the short-circuit evaluation behavior of their built-in counterparts because the expressions on both sides of the operator must be evaluated to pass as arguments, unlike the built-in operators which evaluate the second operand conditionally based on the first operand's value.

It Is Impossible to Get Short-Circuit Behavior for Overloaded Operator