If the heat of fusion for water is 80.cal/g,how many calories are needed to melt 45.0 g of ice at 0 °C?
A)3.6 cal
B)3.6 × cal
C)1.8 cal
D)80.cal
E)0.56 cal

Question

If the heat of fusion for water is 80.cal/g,how many calories are needed to melt 45.0 g of ice at 0 °C?
A)3.6 cal 
B)3.6 × cal 
C)1.8 cal 
D)80.cal 
E)0.56 cal

Quizplus · Accepted Answer

Heat of fusion = 80 cal/g
Mass of ice = 45.0 g
Therefore, the number of calories needed to melt the ice = (heat of fusion) x (mass of ice) = 80 cal/g x 45.0 g = 3.6 x 10^3 cal or 3.6 x 10^11 cal (scientific notation). The closest answer choice is B.

If the Heat of Fusion for Water Is 80