For the following question(s),consider the following equation. 2Mg + O 2 → 2MgO -How many grams of hydrogen are needed to produce 1.80 g of water according to this equation? 2H₂ + O₂ → 2H₂O A)0.101 g B)0.180 g C)0.201 g D)2.01 g E)4.02 g

Question

Quizplus · Accepted Answer

To find the amount of hydrogen needed, we need to use stoichiometry. The balanced equation shows that 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water. Therefore, 1 mole of water is produced from 2 moles of hydrogen.

First, we need to convert the given mass of water to moles:

1.80 g H2O x (1 mol H2O/18.015 g H2O) = 0.0999 mol H2O

Since 2 moles of hydrogen are needed to produce 1 mole of water, we can find the moles of hydrogen needed:

0.0999 mol H2O x (2 mol H2/1 mol H2O) = 0.1998 mol H2

Finally, we can convert moles of hydrogen to grams:

0.1998 mol H2 x (2.016 g H2/1 mol H2) = 0.401 g H2

Rounding to three significant figures, the answer is C, 0.201 g.

For the Following Question(s),consider the Following Equation