The conversion of glucose-6-phosphate to glucose-1-phosphate has a ΔG°′ of 8.4 kJ/mol. What can be said about the value of K_eq? A) K_eq 1 B) K_eq = 1 C) K_eq

Question

The conversion of glucose-6-phosphate to glucose-1-phosphate has a ΔG°′ of 8.4 kJ/mol. What can be said about the value of K_eq? A) K_eq > 1 B) K_eq = 1 C) K_eq < 1 D) cannot be determined

Quizplus · Accepted Answer

The ΔG°′ value tells us that the reaction is not spontaneous and requires energy input to proceed. Therefore, the equilibrium constant (K_eq) must be less than 1, indicating that the reactants are favored over the products at equilibrium.

The Conversion of Glucose-6-Phosphate to Glucose-1-Phosphate Has a ΔG°′ of 8.4