A college basketball player makes 5/6 of his free throws. Assuming free throws are independent, the probability that he makes exactly three of his next four free throws is:
A) .
B) .
C) .
D) .

Question

A college basketball player makes 5/6 of his free throws. Assuming free throws are independent, the probability that he makes exactly three of his next four free throws is:
A) . 
B) . 
C) . 
D) .

Quizplus · Accepted Answer

The player makes 5/6 of his free throws, which means he misses 1/6 of the time. We can use the binomial probability formula to solve this problem:
P(3 hits in 4 attempts) = C(4,3)*(5/6)^3*(1/6)^1 = 4*(125/216)*(1/6) = 25/1296
Therefore, the probability that he makes exactly three of his next four free throws is 25/1296, which is approximately 0.0193 or 1.93%. The closest option is C: 11eaa566_9d1b_bfb9_a0f6_55e45116f95f_TB5064_11.

A College Basketball Player Makes 5/6 of His Free Throws