cis-3-Methylcyclopentanol is treated with CH₃SO₂Cl in the presence of a base.The product of the reaction then is allowed to react with KI in methanol.What is the final product? A)trans-1-Iodo-3-methylcyclopentane B)cis-1-Iodo-3-methylcyclopentane C)1-Methylcyclopentene D)2-Methylcyclopentene E)3-Methylcyclopentene

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The reaction sequence described involves the conversion of cis-3-Methylcyclopentanol to its corresponding alkyl halide using a sulfuryl chloride (SO2Cl2) in the presence of a base, followed by a nucleophilic substitution with KI in methanol. The use of SO2Cl2 in the presence of a base converts the alcohol to a good leaving group, which is then substituted by iodide ion from KI. The stereochemistry changes from cis to trans due to the backside attack mechanism (SN2) of the nucleophilic substitution, leading to the formation of trans-1-Iodo-3-methylcyclopentane.

Cis-3-Methylcyclopentanol Is Treated with CH3SO2Cl in the Presence of a Base.The

Cis-3-Methylcyclopentanol Is Treated with CH₃SO₂Cl in the Presence of a Base.The