The reaction between 2-methyl-2-pentanol and HBr to yield 2-methyl-2-pentene is probably: A)an S_N1-type reaction involving the protonated alcohol as the substrate. B)an S_N2-type reaction involving the protonated alcohol as the substrate. C)an E1-type reaction involving the protonated alcohol as the substrate. D)an E2-type reaction involving the protonated alcohol as the substrate. E)an epoxidation reaction.

Question

Quizplus · Accepted Answer

The reaction between 2-methyl-2-pentanol and HBr to yield 2-methyl-2-pentene involves the formation of a carbocation intermediate from the protonated alcohol, which then loses a water molecule to form the alkene. This is characteristic of an E1 (Elimination Unimolecular) reaction.

The Reaction Between 2-Methyl-2-Pentanol and HBr to Yield 2-Methyl-2-Pentene Is