The free radical chlorination of 3-chloropentane forms a mixture of dichloropentanes which,on precise fractional distillation,affords these fractions:
A)4 fractions,none optically active
B)4 fractions,2 optically active
C)7 fractions,4 optically active
D)7 fractions,6 optically active
E)7 fractions,all optically active

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The Answer of The free radical chlorination of 3-chloropentane forms a mixture of dichloropentanes which,on precise fractional distillation,affords these fractions:
A)4 fractions,none optically active
B)4 fractions,2 optically active
C)7 fractions,4 optically active
D)7 fractions,6 optically active
E)7 fractions,all optically active

The Free Radical Chlorination of 3-Chloropentane Forms a Mixture of Dichloropentanes