An object at temperature 227 $\circ$ C radiates energy at a net rate of R J/s. By what factor would the net rate of energy loss increase if the same object were at a temperature of 427 $\circ$ C? Assume the surrounding temperature is 0 $\circ$ C.
A)4.1
B)3.8
C)12.5
D)8.3
E)6.7

Question

Quizplus · Accepted Answer

The net rate of energy loss is proportional to the fourth power of the temperature. Therefore, the net rate of energy loss would increase by a factor of (427/227)^4 = 4.1.

An Object at Temperature 227 ∘\circ∘ C Radiates Energy at a Net Rate of R J/s

An Object at Temperature 227^$\circ$C Radiates Energy at a Net Rate of R J/s