Bernoulli's equation for nonviscous flow can be stated as P₁ + $\rho$gy₁ + $\rho$v₁2 = P₂ + $\rho$gy₂ + $\rho$v₂2 A fluid is flowing through a horizontal tube that changes in cross-sectional area from A₁= 0.75 cm² to A₂ = 0.030 cm². When v₁ = 3.5 cm/s, $\rho$ = 1.4 g/cm³, and viscosity is neglected, the difference between pressure P₂ at A₂ and P₁ at A₁ is A) 54 $\times$ 10³ dyn/cm², with P₁ higher. B) 59 dyn/cm², with P₂ higher. C) 59 dyn/cm², with P₁ higher. D) 8.3 $\times$ 10² dyn/cm², with P₂ higher. E) None of these is correct.

Question

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The Answer of Bernoulli's equation for nonviscous flow can be stated as P₁ + $\rho$gy₁ + $\rho$v₁2 = P₂ + $\rho$gy₂ + $\rho$v₂2 A fluid is flowing through a horizontal tube that changes in cross-sectional area from A₁= 0.75 cm² to A₂ = 0.030 cm². When v₁ = 3.5 cm/s, $\rho$ = 1.4 g/cm³, and viscosity is neglected, the difference between pressure P₂ at A₂ and P₁ at A₁ is A) 54 $\times$ 10³ dyn/cm², with P₁ higher. B) 59 dyn/cm², with P₂ higher. C) 59 dyn/cm², with P₁ higher. D) 8.3 $\times$ 10² dyn/cm², with P₂ higher. E) None of these is correct.

Bernoulli's Equation for Nonviscous Flow Can Be Stated as P1 ρ\rhoρ

Bernoulli's Equation for Nonviscous Flow Can Be Stated as
P₁ $\rho$