The angular acceleration of the flywheel of a generator is given by
$\alpha$ (t) = 6bt - 12ct²
Where b and c are constants and $\alpha$ is in rad/s² provided t is in seconds. If the initial angular velocity is taken to be $\omega$ ₀, the angular velocity at time t is given by

Question

The angular acceleration of the flywheel of a generator is given by

\alpha

(t) = 6bt - 12ct²
Where b and c are constants and

\alpha

is in rad/s² provided t is in seconds. If the initial angular velocity is taken to be

\omega

₀, the angular velocity at time t is given by

Quizplus · Accepted Answer

We can find the angular velocity by integrating the angular acceleration with respect to time: F1F1F1S1F1F1F10₀ + ∫[6bt-12ct²]dt F1F1F1S1F1F1F10₀ + [3bt^2 - 4ct^3/3] + C Since the angular velocity at time zero is F1F1F1S1F1F1F10₀, C = 0, and we get: F1F1F1S1F1F1F10₀ + 3bt^2 - 4ct^3/3 which matches option C.

The Angular Acceleration of the Flywheel of a Generator Is α\alphaα

The Angular Acceleration of the Flywheel of a Generator Is $\alpha$