Determine whether the given values of the variables are solutions of the equation. $\left( x - \frac { 1 } { 2 } \right) + ( 2 x - 1 ) = 2 \left( x - \frac { 1 } { 2 } \right) - ( 1 - x ) + \frac { 1 } { 2 }$
(a)
$x = \frac { 3 } { 2 }$
(b)
$x = \frac { 1 } { 2 }$

Question

Determine whether the given values of the variables are solutions of the equation. $\left( x - \frac { 1 } { 2 } \right) + ( 2 x - 1 ) = 2 \left( x - \frac { 1 } { 2 } \right) - ( 1 - x ) + \frac { 1 } { 2 }$ 
(a)
 $x = \frac { 3 } { 2 }$ 
(b)
 $x = \frac { 1 } { 2 }$

Quizplus · Accepted Answer

The Answer of Determine whether the given values of the variables are solutions of the equation. $\left( x - \frac { 1 } { 2 } \right) + ( 2 x - 1 ) = 2 \left( x - \frac { 1 } { 2 } \right) - ( 1 - x ) + \frac { 1 } { 2 }$ 
(a)
 $x = \frac { 3 } { 2 }$ 
(b)
 $x = \frac { 1 } { 2 }$

Determine Whether the Given Values of the Variables Are Solutions (x−12)+(2x−1)=2(x−12)−(1−x)+12\left( x - \frac { 1 } { 2 } \right) + ( 2 x - 1 ) = 2 \left( x - \frac { 1 } { 2 } \right) - ( 1 - x ) + \frac { 1 } { 2 }(x−21​)+(2x−1)=2(x−21​)−(1−x)+21​

Determine Whether the Given Values of the Variables Are Solutions $\left( x - \frac { 1 } { 2 } \right) + ( 2 x - 1 ) = 2 \left( x - \frac { 1 } { 2 } \right) - ( 1 - x ) + \frac { 1 } { 2 }$