Solve the system of linear equations. $$\left\{ \begin{array} { r }
x + 3 y = 0 \
2 x + 7 y + 2 z = - 1 \
x + 4 y + 3 z = - 4
\end{array} \right.$$

Name: Solve the system of linear equations. \[\left\{ \begin{array} { r } x + 3 y = 0 \\ 2 x + 7 y + 2 z = - 1 \\ x + 4 y + 3 z = - 4 \end{array} \right.\]
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Question

Solve the system of linear equations. $$\left\{ \begin{array} { r } 
x + 3 y = 0 \
2 x + 7 y + 2 z = - 1 \
x + 4 y + 3 z = - 4
\end{array} \right.$$

Quizplus · Accepted Answer

The Answer of Solve the system of linear equations. $$\left\{ \begin{array} { r } 
x + 3 y = 0 \
2 x + 7 y + 2 z = - 1 \
x + 4 y + 3 z = - 4
\end{array} \right.$$

Solve the System of Linear Equations {x+3y=02x+7y+2z=−1x+4y+3z=−4\left\{ \begin{array} { r } x + 3 y = 0 \\2 x + 7 y + 2 z = - 1 \\x + 4 y + 3 z = - 4\end{array} \right.⎩⎨⎧​x+3y=02x+7y+2z=−1x+4y+3z=−4​

Solve the System of Linear Equations $\left\{ \begin{array} { r } x + 3 y = 0 \\2 x + 7 y + 2 z = - 1 \\x + 4 y + 3 z = - 4\end{array} \right.$