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Solve the Given Equation 2sin⁡2θ−7sin⁡θ+3=02 \sin ^ { 2 } \theta - 7 \sin \theta + 3 = 0

Question 93

Essay

Solve the given equation. 2sin⁡2θ−7sin⁡θ+3=02 \sin ^ { 2 } \theta - 7 \sin \theta + 3 = 0

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