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Prove sin⁡(x+y)sin⁡xsin⁡y=cot⁡x+cot⁡y\frac { \sin ( x + y ) } { \sin x \sin y } = \cot x + \cot y

Question 48

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Prove sin⁡(x+y)sin⁡xsin⁡y=cot⁡x+cot⁡y\frac { \sin ( x + y ) } { \sin x \sin y } = \cot x + \cot y .

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