Make the indicated trigonometric substitution in the given algebraic expression and simplify. Assume that $0 \leq x \leq \pi / 2$ $\sqrt { x ^ { 2 } - 25 } , \quad x = 5 \sec \theta$

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The Answer of Make the indicated trigonometric substitution in the given algebraic expression and simplify. Assume that $0 \leq x \leq \pi / 2$ $\sqrt { x ^ { 2 } - 25 } , \quad x = 5 \sec \theta$

Make the Indicated Trigonometric Substitution in the Given Algebraic Expression 0≤x≤π/20 \leq x \leq \pi / 20≤x≤π/2

Make the Indicated Trigonometric Substitution in the Given Algebraic Expression $0 \leq x \leq \pi / 2$