How would you define $f(3)$ in order to make f continuous at 3 ? $f(x)=\frac{x^{2}-3 x-7}{x-3}$
A) $f(3)=1$
B) $f(3)=3$
C) $f(3)=-3$
D) $f(3)=0$
E) None of these

Name: How would you define $f(3)$ in order to make f continuous at 3 ? $f(x)=\frac{x^{2}-3 x-7}{x-3}$ A) $f(3)=1$ B) $f(3)=3$ C) $f(3)=-3$ D) $f(3)=0$ E) None of these
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The Answer of How would you define $f(3)$ in order to make f continuous at 3 ? $f(x)=\frac{x^{2}-3 x-7}{x-3}$
A) $f(3)=1$
B) $f(3)=3$
C) $f(3)=-3$
D) $f(3)=0$
E) None of these

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How Would You Define $f(3)$ In Order to Make F Continuous at 3