Water flows from a tank of constant cross-sectional area 50 $\mathrm{ft}^{2}$ through an orifice of constant cross-sectional area $\frac{1}{4}$ $\mathrm{ft}^{2}$ located at the bottom of the tank. Initially, the height of the water in the tank was 20 ft, and t sec later it was given by the equation $2 \sqrt{h}+\frac{1}{25} t-2 \sqrt{20}=0 \quad \quad \quad 0 \leq t \leq 50 \sqrt{20}$ How fast was the height of the water decreasing when its height was 2 ft?
A) $100 \sqrt{5}-50 \sqrt{2}$ ft/sec
B) $100 \sqrt{5}-50 \sqrt{2}$ ft/sec.
C) $\frac{2}{25}$ ft/sec
D) $\frac{\sqrt{2}}{25}$ ft/sec

Question

Water flows from a tank of constant cross-sectional area 50 $\mathrm{ft}^{2}$ through an orifice of constant cross-sectional area $\frac{1}{4}$ $\mathrm{ft}^{2}$ located at the bottom of the tank. Initially, the height of the water in the tank was 20 ft, and t sec later it was given by the equation $2 \sqrt{h}+\frac{1}{25} t-2 \sqrt{20}=0 \quad \quad \quad 0 \leq t \leq 50 \sqrt{20}$ How fast was the height of the water decreasing when its height was 2 ft? 
A) $100 \sqrt{5}-50 \sqrt{2}$ ft/sec 
B) $100 \sqrt{5}-50 \sqrt{2}$ ft/sec. 
C) $\frac{2}{25}$ ft/sec 
D) $\frac{\sqrt{2}}{25}$ ft/sec

Quizplus · Accepted Answer

The Answer of Water flows from a tank of constant cross-sectional area 50 $\mathrm{ft}^{2}$ through an orifice of constant cross-sectional area $\frac{1}{4}$ $\mathrm{ft}^{2}$ located at the bottom of the tank. Initially, the height of the water in the tank was 20 ft, and t sec later it was given by the equation $2 \sqrt{h}+\frac{1}{25} t-2 \sqrt{20}=0 \quad \quad \quad 0 \leq t \leq 50 \sqrt{20}$ How fast was the height of the water decreasing when its height was 2 ft? 
A) $100 \sqrt{5}-50 \sqrt{2}$ ft/sec 
B) $100 \sqrt{5}-50 \sqrt{2}$ ft/sec. 
C) $\frac{2}{25}$ ft/sec 
D) $\frac{\sqrt{2}}{25}$ ft/sec

Water Flows from a Tank of Constant Cross-Sectional Area 50 ft2\mathrm{ft}^{2}ft2

Water Flows from a Tank of Constant Cross-Sectional Area 50 $\mathrm{ft}^{2}$