Use the Trapezoidal Rule to approximate the integral with answers rounded to four decimal places. $\int_{0}^{2} \frac{d x}{\sqrt{x^{3}+4}} ; \quad n=6$
A) 0.8528
B) 0.9842
C) 0.4921
D) 0.4695

Question

Quizplus · Accepted Answer

The Trapezoidal Rule with $ n = 6 $ approximates the integral by dividing the interval $[0, 2]$ into 6 equal parts, calculating the function values at these points, and applying the trapezoidal formula. The correct approximation rounds to 0.8528.

Use the Trapezoidal Rule to Approximate the Integral with Answers ∫02dxx3+4;n=6\int_{0}^{2} \frac{d x}{\sqrt{x^{3}+4}} ; \quad n=6∫02​x3+4​dx​;n=6

Use the Trapezoidal Rule to Approximate the Integral with Answers $\int_{0}^{2} \frac{d x}{\sqrt{x^{3}+4}} ; \quad n=6$