Suppose that a population develops according to the logistic equation $\frac { d P } { d t } = 0.06 P - 0.0006 P ^ { 2 }$ , where t is measured in weeks. What is the carrying capacity?
A) $K = 600$
B) $K = 100$
C) $K = 0.0006$
D) $K = 0.06$
E) $K = 700$

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The Answer of Suppose that a population develops according to the logistic equation $\frac { d P } { d t } = 0.06 P - 0.0006 P ^ { 2 }$ , where t is measured in weeks. What is the carrying capacity?
A) $K = 600$
B) $K = 100$
C) $K = 0.0006$
D) $K = 0.06$
E) $K = 700$

Suppose That a Population Develops According to the Logistic Equation dPdt=0.06P−0.0006P2\frac { d P } { d t } = 0.06 P - 0.0006 P ^ { 2 }dtdP​=0.06P−0.0006P2

Suppose That a Population Develops According to the Logistic Equation $\frac { d P } { d t } = 0.06 P - 0.0006 P ^ { 2 }$