Find an equation of the tangent line to the curve at the point corresponding to the value of the parameter. $x = e ^ { \sqrt { t } }$ , $y = t - \ln t ^ { 6 }$ ; $t = 1$

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The Answer of Find an equation of the tangent line to the curve at the point corresponding to the value of the parameter. $x = e ^ { \sqrt { t } }$ , $y = t - \ln t ^ { 6 }$ ; $t = 1$

Find an Equation of the Tangent Line to the Curve x=etx = e ^ { \sqrt { t } }x=et​

Find an Equation of the Tangent Line to the Curve $x = e ^ { \sqrt { t } }$