The initial value problem $y ^ { \prime } = \sqrt { y ^ { 2 } - 16 } , y \left( x _ { 0 } \right) = y _ { 0 }$ has a unique solution guaranteed by Theorem 1.1 if
A) $y _ { 0 } = 4$
B) $y _ { 0 } = - 4$
C) $y _ { 0 } = 0$
D) $y _ { 0 } = 8$
E) $y _ { 0 } = 1$

Question

Quizplus · Accepted Answer

The Answer is D

The Initial Value Problem y′=y2−16,y(x0)=y0y ^ { \prime } = \sqrt { y ^ { 2 } - 16 } , y \left( x _ { 0 } \right) = y _ { 0 }y′=y2−16​,y(x0​)=y0​

The Initial Value Problem $y ^ { \prime } = \sqrt { y ^ { 2 } - 16 } , y \left( x _ { 0 } \right) = y _ { 0 }$