The solution of the system of differential equations in the two previous problems is
A) $x = 10 e ^ { - 0.1 t } , y = 12.5 \left( e ^ { - 0.1 t } - e ^ { - 0.5 t } \right) , z = 10 - 12.5 e ^ { - 0.1 t } + 2.5 e ^ { - 0.5 t }$
B) $x = 10 e ^ { - 0.1 t } , y = 12.5 \left( e ^ { - 0.5 t } - e ^ { - 0.1 t } \right) , z = 10 - 12.5 e ^ { - 0.5 t } + 2.5 e ^ { - 0.1 t }$
C) $x = 10 e ^ { - 0.5 t } , y = 12.5 \left( e ^ { - 0.5 t } - e ^ { - 0.1 t } \right) , z = 10 - 12.5 e ^ { - 0.2 t } + 2.5 e ^ { - 0.3 t }$
D) $x = 10 e ^ { - 0.5 t } , y = 12.5 \left( e ^ { - 0.1 t } - e ^ { - 0.5 t } \right) , z = 10 - 12.5 e ^ { - 0.5 t } + 2.5 e ^ { - 0.1 t }$
E) $x = 10 e ^ { - 0.5 t } , y = 12.5 \left( e ^ { - 0.1 t } - e ^ { - 0.5 t } \right) , z = 10 - 12.5 e ^ { - 0.1 t } + 2.5 e ^ { - 0.5 t }$

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The Answer of The solution of the system of differential equations in the two previous problems is
A) $x = 10 e ^ { - 0.1 t } , y = 12.5 \left( e ^ { - 0.1 t } - e ^ { - 0.5 t } \right) , z = 10 - 12.5 e ^ { - 0.1 t } + 2.5 e ^ { - 0.5 t }$
B) $x = 10 e ^ { - 0.1 t } , y = 12.5 \left( e ^ { - 0.5 t } - e ^ { - 0.1 t } \right) , z = 10 - 12.5 e ^ { - 0.5 t } + 2.5 e ^ { - 0.1 t }$
C) $x = 10 e ^ { - 0.5 t } , y = 12.5 \left( e ^ { - 0.5 t } - e ^ { - 0.1 t } \right) , z = 10 - 12.5 e ^ { - 0.2 t } + 2.5 e ^ { - 0.3 t }$
D) $x = 10 e ^ { - 0.5 t } , y = 12.5 \left( e ^ { - 0.1 t } - e ^ { - 0.5 t } \right) , z = 10 - 12.5 e ^ { - 0.5 t } + 2.5 e ^ { - 0.1 t }$
E) $x = 10 e ^ { - 0.5 t } , y = 12.5 \left( e ^ { - 0.1 t } - e ^ { - 0.5 t } \right) , z = 10 - 12.5 e ^ { - 0.1 t } + 2.5 e ^ { - 0.5 t }$

The Solution of the System of Differential Equations in the Two