Using the convolution theorem, we find that $\mathcal { L } ^ { - 1 } \left\{ 1 / \left( ( s + 1 ) \left( s ^ { 2 } + 1 \right) \right) \right\} =$
A) $\left( e ^ { - t } + \sin t - \cos t \right) / 2$
B) $\left( e ^ { t } + \sin t - \cos t \right) / 2$
C) $\left( e ^ { - t } + \sin t + \cos t \right) / 2$
D) $\left( e ^ { t } - \sin t - \cos t \right) / 2$
E) $\left( e ^ { - t } - \sin t - \cos t \right) / 2$

Question

Quizplus · Accepted Answer

The Answer is A

Using the Convolution Theorem, We Find That L−1{1/((s+1)(s2+1))}=\mathcal { L } ^ { - 1 } \left\{ 1 / \left( ( s + 1 ) \left( s ^ { 2 } + 1 \right) \right) \right\} =L−1{1/((s+1)(s2+1))}=

Using the Convolution Theorem, We Find That $\mathcal { L } ^ { - 1 } \left\{ 1 / \left( ( s + 1 ) \left( s ^ { 2 } + 1 \right) \right) \right\} =$