The electric field in a region of space varies according to
E = (1.25 N/C) sin 1500t
Where t is in seconds. The maximum displacement current through a 2.00-m² area perpendicular to E is approximately

Question

Quizplus · Accepted Answer

The displacement current density is given by J_d = ε₀ (dE/dt). The maximum value of dE/dt is the amplitude of the derivative of E, which is 1.25 * 1500 N/C/s. The maximum displacement current is J_d * area = ε₀ * 1.25 * 1500 * 2.00 m² = 33.2 nA.

The Electric Field in a Region of Space Varies According