A straight wire segment 3.0 m long makes an angle of 28º with a uniform magnetic field of 1.0 T. The magnitude of the force on the wire if it carries a current of 1.5 A is approximately
A) 2.1 N
B) 4.0 N
C) 1.4 N
D) 0.70 N
E) 4.7 N

Question

Quizplus · Accepted Answer

The force on a current-carrying wire in a magnetic field is given by F = I * L * B * sin(θ). Substituting the given values: F = 1.5 A * 3.0 m * 1.0 T * sin(28º) ≈ 2.1 N.

A Straight Wire Segment 3