In this circuit, two batteries, one with a potential difference of 10 V and the other with a potential difference of 20 V, are connected in series across a resistance of 90 $\Omega$. The power delivered by the 10-V battery is approximately
A) 5.4 W
B) 15 W
C) 10 W
D) 3.3 W
E) 6.7 W

Question

In this circuit, two batteries, one with a potential difference of 10 V and the other with a potential difference of 20 V, are connected in series across a resistance of 90 $\Omega$. The power delivered by the 10-V battery is approximately
A) 5.4 W 
B) 15 W 
C) 10 W 
D) 3.3 W 
E) 6.7 W

Quizplus · Accepted Answer

First, we need to find the total voltage that is being applied across the resistor. Since the batteries are connected in series, their voltages add up, so:

V(total) = 10 V + 20 V = 30 V

Next, we can use Ohm's law to find the current flowing through the resistor:

I = V/R = 30 V / 90 Ω = 1/3 A

Now, we can find the power delivered by the 10 V battery using the formula:

P = VI

Since the 10 V battery is in series with the resistor, it is delivering the same current as the resistor, so:

P = 10 V x 1/3 A = 3.3 W

Therefore, the answer is D) 3.3 W.

In This Circuit, Two Batteries, One with a Potential Difference Ω\OmegaΩ

In This Circuit, Two Batteries, One with a Potential Difference $\Omega$