A storage battery with emf 6.4 V and internal resistance 0.080 $\Omega$ is being charged by a current of 15 A.The power loss in internal heating of the battery is
A)18 W
B)96 W
C)1.2 W
D)80 W
E)0.11 kW

Question

Quizplus · Accepted Answer

The power loss due to internal heating in the battery can be calculated using the formula $P = I^2R$, where $I$ is the current and $R$ is the internal resistance. Substituting the given values, $P = (15 A)^2 \times 0.080 \Omega = 18 W$.

A Storage Battery with Emf 6 Ω\OmegaΩ Is Being Charged by a Current of 15 A

A Storage Battery with Emf 6 $\Omega$ Is Being Charged by a Current of 15 A