A wire of length L = 3.0 m.When an electric field of E = 0.5 V/m is applied to the wire,the current is 1.5 A.The resistance of the wire is
A)0.53 $\Omega$
B)8.0 $\Omega$
C)5.33 $\Omega$
D)0.13 $\Omega$
E)1.0 $\Omega$

Question

Quizplus · Accepted Answer

The resistance of the wire can be calculated using Ohm's law, which states that the resistance (R) is equal to the voltage (V) divided by the current (I). Given that the electric field (E) is 0.5 V/m and the length of the wire (L) is 3.0 m, the voltage across the wire is V = E * L = 0.5 V/m * 3.0 m = 1.5 V. With a current (I) of 1.5 A, the resistance (R) is R = V / I = 1.5 V / 1.5 A = 1.0 Ω.

A Wire of Length L = 3 Ω\OmegaΩ B)80 Ω\OmegaΩ C)533 Ω\OmegaΩ D)013 Ω\OmegaΩ

A Wire of Length L = 3 $\Omega$ B)80 $\Omega$ C)533 $\Omega$ D)013 $\Omega$