The reduced mass of a system of two particles whose masses are m₁ and m₂ is A)µ = (m₁ + m₂)/m₁ · m₂ B)µ = (m₁ + m₂)/m₁ C)µ = m₁/(m₁ + m₂) D)µ = m₁ · m₂/m₁ E)µ = m₁ · m₂/(m₁ + m₂)

Question

Quizplus · Accepted Answer

The formula for reduced mass is µ = m1m2/(m1+m2), where m1 and m2 are the masses of the particles. Substituting the given masses, we get µ = m₁·m₂/(m₁ + m₂), which is option E.

The Reduced Mass of a System of Two Particles Whose