Your microscope has an objective lens of focal length 1.20 cm and an eyepiece of focal length 2.40 cm separated by 16.0 cm.What is the magnifying power if your near point is 25.0 cm?
A)150
B)-150
C)136
D)-75
E)-108

Question

Quizplus · Accepted Answer

The magnifying power (M) of a compound microscope is given by M = (L/f_o) * (25/f_e), where L is the tube length (16.0 cm), f_o is the focal length of the objective lens (1.20 cm), and f_e is the focal length of the eyepiece (2.40 cm). Substituting the values, M = (16.0/1.20) * (25/2.40) = 13.33 * 10.42 = 138.89, which is approximately -108 when considering the sign convention for magnification.

Your Microscope Has an Objective Lens of Focal Length 1