A 200-turn coil rotates in a magnetic field of magnitude 0.25 T at a frequency of 60 Hz.The area of the coil is 5.0 cm².What is the maximum EMF in the coil? A)1.5 V B)4.5 V C)9.0 V D)9.4 V E)24 V

Question

Quizplus · Accepted Answer

The maximum EMF of a rotating coil is given by:

EMF = NABωsin(ωt)

where N is the number of turns, A is the area of the coil, B is the magnitude of the magnetic field, ω is the angular frequency (2πf), and t is the time.

Substituting the given values, we get:

EMF = (200)(5.0×10^(-4))(0.25)(2π(60))sin(2π(60)t_max)

where t_max is the time at which the maximum EMF occurs, which is when sin(2π(60)t_max) = 1.

Therefore,

EMF_max = (200)(5.0×10^(-4))(0.25)(2π(60))(1) = 9.42 V

which is closest to option D) 9.4 V.

A 200-Turn Coil Rotates in a Magnetic Field of Magnitude