Three capacitors 2 $\mu$F,4 $\mu$F and 8 $\mu$F are connected in parallel across a 120-V source.The charge on the 4 $\mu$F capacitor is A)2.4 $\times$ 10^-⁴ C B)9.6 $\times$ 10^-4 C C)2.1 $\times$ 10³ C D)1.7 $\times$ 10^-3 C E)4.8 $\times$ 10^-4 C

Question

Quizplus · Accepted Answer

In a parallel combination of capacitors, the voltage across each capacitor is the same as the source voltage. 
Total capacitance, C= 2+4+8= 14 μF.
Charge Q= CV, where V= 120 V.
Therefore, Q= 14*10^-6 *120= 1.68*10^-3 C.
The charge on each capacitor is Q, so the charge on the 4 μF capacitor is 4*10^-6 *120= 4.8*10^-4 C.
Hence, the best choice is B, which represents the answer in coulombs after converting to scientific notation.

Three Capacitors 2 μ\muμ F,4 μ\muμ F and 8 μ\muμ F Are Connected in Parallel Across a 120-V Source

Three Capacitors 2 $\mu$ F,4 $\mu$ F and 8 $\mu$ F Are Connected in Parallel Across a 120-V Source