A large,flat conducting plate has a surface charge density $\sigma$ = 8.0 $\times$ 10^-9 C/m² on one of its surfaces.What is the magnitude of the electric field 10 µm from this plate? A)72 N/C B)0.23 kN/C C)0.90 kN/C D)90 MN/C E)9.0 $\times$ 10¹² N/C

Question

Quizplus · Accepted Answer

The electric field due to a large, flat conducting plate is given by:
E = σ/2ε₀
where σ is the surface charge density and ε₀ is the permittivity of free space.
Plugging in the given values, we get:
E = (8.0 × 10⁻⁹ C/m²) / (2 × 8.85 × 10⁻¹² C²/Nm²)
E = 0.90 × 10³ N/C = 0.90 kN/C
Thus, the correct answer is (C).

A Large,flat Conducting Plate Has a Surface Charge Density σ\sigmaσ = 80

A Large,flat Conducting Plate Has a Surface Charge Density $\sigma$ = 80