A molecule of HCl has a dipole moment of 3.39 $\times$ 10^-30 C · m.If we assume full donation of the hydrogen electron to the chlorine,then calculate the distance between the charge centers. A)4.72 $\times$ 10¹⁰ m B)1.06 $\times$ 10^-11 m C)4.24 $\times$ 10^-11 m D)2.12 $\times$ 10^-11 m E)2.44 $\times$ 10^-11 m

Question

Quizplus · Accepted Answer

The distance between the charge centers can be calculated using the formula: 
distance = dipole moment / charge magnitude 
In this case, the dipole moment is given as 3.39 x 10^-30 C·m and the charge magnitude is the charge on an electron, which is 1.6 x 10^-19 C. 
Therefore, distance = (3.39 x 10^-30 C·m) / (1.6 x 10^-19 C) = 2.12 x 10^-11 m = 2.12 Å 
The answer is option D.

A Molecule of HCl Has a Dipole Moment of 3 ×\times×

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