An electric dipole p makes an angle of 30 $\circ$ with a uniform electric field of magnitude 300 N/C.If the torque on the dipole is 3.00 $\times$ 10^-12 N · m then calculate the magnitude of the dipole moment p. A)2.00 $\times$ 10^-14 C · m B)1.00 $\times$ 10^-14 C · m C)4.00 $\times$ 10^-14 C · m D)1.15 $\times$ 10^-14 C · m E)1.73 $\times$ 10^-14 C · m

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The torque on an electric dipole in a uniform electric field is given by:$$\tau = pE\sin\theta$$where:* $\tau$ is the torque* $p$ is the dipole moment* $E$ is the electric field strength* $\theta$ is the angle between the dipole moment and the electric fieldIn this problem, we are given:* $\tau = 3.00 \times 10^{-12} \text{ N}\cdot\text{m}$* $E = 300 \text{ N/C}$* $\theta = 30^\circ$We can solve for $p$ by rearranging the equation:$$p = \frac{\tau}{E\sin\theta}$$Plugging in the given values, we get:$$p = \frac{3.00 \times 10^{-12} \text{ N}\cdot\text{m}}{(300 \text{ N/C})\sin30^\circ} = 2.00 \times 10^{-14} \text{ C}\cdot\text{m}$$Therefore, the magnitude of the dipole moment is 2.00 x 10^-14 C m.

An Electric Dipole P Makes an Angle of 30 ∘\circ∘ with a Uniform Electric Field of Magnitude 300 N/C

An Electric Dipole P Makes an Angle of 30^$\circ$ with a Uniform Electric Field of Magnitude 300 N/C