Two sound waves,one wave is given by y₁ = p_o sin ($\omega$₁t),and the other by y₂ = p_o sin ($\omega$₂t),where $\omega$₁ differs from $\omega$₂ by a rad/s.The maximum sound intensity of the beat frequency is A)p_o² B)2p_o² C)4p_o² D)8p_o² E) 0

Question

Quizplus · Accepted Answer

The beat frequency is given by: fbeat = |f1 - f2| = |(ω1/2π) - (ω2/2π)| = |(ω1 - ω2)/2π| Since ω1 differs from ω2 by a rad/s, we can write: ω1 = ω2 + 2π Substituting this in the expression for fbeat gives: fbeat = |(ω2 + 2π - ω2)/2π| = 1/2 The maximum intensity of the beat frequency is given by: Imax = (p1o^2 + p2o^2 + 2p1o p2o cos(2πfbeatt))/2 Substituting fbeat = 1/2 and simplifying, we get: Imax = 4p1o p2o/2 = 2p1o p2o Using the given values, we have: Imax = 4p_o² Therefore, the correct answer is C.

Two Sound Waves,one Wave Is Given by Y1 = Po ω\omegaω

Two Sound Waves,one Wave Is Given by Y₁ = P_o $\omega$