The bulk modulus of water is 2.0 $\times$ 10⁹ N/m².By how much must the pressure be increased to reduce the volume of 1.0 kg of water from 1.00 to 0.998 L? A)2.0 $\times$ 10⁶ N/m² B)4.0 $\times$ 10⁶ N/m² C)20 $\times$ 10⁶ N/m² D)40 $\times$ 10⁶ N/m² E)8.0 $\times$ 10⁶ N/m²

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Quizplus · Accepted Answer

The bulk modulus formula is B = -ΔP/(ΔV/V). Here, ΔV = 0.002 L, V = 1.00 L, and B = 2.0 x 10^9 N/m^2. Solving for ΔP gives ΔP = B * (ΔV/V) = 2.0 x 10^9 * (0.002/1.00) = 4.0 x 10^6 N/m^2.

The Bulk Modulus of Water Is 2 ×\times× 109 N/m2 ×\times× 106 N/m2 B)4

The Bulk Modulus of Water Is 2 $\times$ 10⁹ N/m² $\times$ 10⁶ N/m²
B)4